TS EAMCET · Physics · Laws of Motion

The y-component of vector $\vec{A}$ is $+ 3.0 m$ . If A makes an angle of $30 °$ counter-clockwise from the positive $y$ - axis, the magnitude of $\vec{A}$ is (assume $\vec{A}$ is in $x - y$ plane)

A $2 \sqrt{3} m$
B $\sqrt{11} m$
C $\sqrt{15} m$
D $\sqrt{21} m$

Verified Solution

Answer & Solution

Correct Answer

(A) $2 \sqrt{3} m$

Step-by-step Solution

Detailed explanation

From the above diagram, we can make the direction of vector now we can find the magnitude of a vector from the order of component, A=A'cos300⇒A'=332=23 m.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

Same subject

Explore more questions on app

From TS EAMCET

Explore more questions on app

The y-component of vector A→ is +3.0 m. If A makes an angle of 30° counter-clockwise from the positive y- axis, the magnitude of A→ is (assume A→ is in x-y plane)

Step-by-step Solution

The y-component of vector $\vec{A}$ is $+ 3.0 m$ . If A makes an angle of $30 °$ counter-clockwise from the positive $y$ - axis, the magnitude of $\vec{A}$ is (assume $\vec{A}$ is in $x - y$ plane)