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TS EAMCET · Physics · Thermodynamics

The total internal energy of 4 moles of a diatomic gas at a temperature of \(27^{\circ} \mathrm{C}\) is (Universal gas constant \(=8.31 \mathrm{~J}\) \(\mathrm{mol}^{-1} \mathrm{~K}^{-1}\) )

  1. A 13.47 kJ
  2. B 4.98 kJ
  3. C 24.93 kJ
  4. D 14.96 kJ
Verified Solution

Answer & Solution

Correct Answer

(C) 24.93 kJ

Step-by-step Solution

Detailed explanation

Total internal energy \(u=n \frac{f}{2} \mathbf{R T}\) for diatomic gas \(\mathrm{f}=5, \mathrm{n}=4\) moles and \(\mathrm{T}=27^{\circ} \mathrm{C}=27+273=300 \mathrm{~K}\) given Therefore \(u=4 \times \frac{5}{2} \times 8.31 \times 300=24.93 \times 10^3 \mathrm{~J}\) or,…
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