TS EAMCET · Physics · Atomic Physics
The ratio of the energies of the electron in the hydrogen atom in the first and second excited states is
- A \(9: 4\)
- B \(4: 1\)
- C \(8: 1\)
- D \(1: 8\)
Answer & Solution
Correct Answer
(A) \(9: 4\)
Step-by-step Solution
Detailed explanation
(a) Energy in Hydrogen atom is given as: \(\begin{aligned} & E=-13.6 \frac{z^2}{n^2} \\ & \therefore \quad E \propto \frac{1}{n^2} \\ & \frac{E_1}{E_2}=\frac{n_2^2}{n_1^2}=\left(\frac{3}{2}\right)^2 \\ & E_1: E_2=9: 4 \end{aligned}\)
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