TS EAMCET · Physics · Magnetic Effects of Current
A \(50 \mathrm{~cm}\) long solenoid has winding of 400 turns. What current must pass through it to produce a magnetic field of induction \(4 \pi \times 10^{-3} \mathrm{~T}\) at the centre?
- A 10.5A
- B 12.5A
- C 25.0A
- D 20.0A
Answer & Solution
Correct Answer
(B) 12.5A
Step-by-step Solution
Detailed explanation
For a solenoid, \(B=\mu_0 n I \Rightarrow n=\frac{N}{L}\) Here, \(\begin{aligned} & B=4 \pi \times 10^{-3} \mathrm{~T} \\ & n=\frac{400}{50 \times 10^{-2}}=\frac{400 \times 100}{50}=800 \text { turns } / \mathrm{m} \end{aligned}\)…
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