TS EAMCET · Physics · Gravitation
A heavy uniform rope is suspended vertically from a ceiling and is in equilibrium. A pulse is generated at the bottom end of the rope as shown. As the pulse travels up the rope, its acceleration at any instant is ( \(\mathrm{g}\) is acceleration due to gravity)
- A Constant and equal to \(\frac{g}{2}\)
- B Variable but equal to \(\frac{g}{2}\) when tiie pulse is exactly at the middle of the string
- C Constant and equal to \(\mathrm{g}\)
- D Variable but equal to \(\mathrm{g}\) when the pulse is exactly at the middle of the string.
Answer & Solution
Correct Answer
(A) Constant and equal to \(\frac{g}{2}\)
Step-by-step Solution
Detailed explanation
Consider a heavy rope which have mass \(\mathrm{M}\) and length \(\mathrm{L}\). \(\mathrm{a}=\mathrm{x} \text { (constant) }\) Tension in rope, \(\mathrm{T}=\frac{\mathrm{M}}{\mathrm{L}} \mathrm{xg}=\mu \mathrm{xg}\) speed of pulse, \(v=\sqrt{\frac{i}{\mu}}\)…
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