TS EAMCET · Physics · Laws of Motion
In the pulley system, the mass of ball is 1.2 times greater than the mass of the rod. The length of the rod is \(50 \mathrm{~cm}\). The ball is set on the same level as the lower end of the rod and then released. What is the acceleration of the rod with which it comes down? Assume the pulleys and threads are massless and friction force is neglected. (Use, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(4 \mathrm{~m} / \mathrm{s}^2\)
- B \(3 \mathrm{~m} / \mathrm{s}^2\)
- C \(2 \mathrm{~m} / \mathrm{s}^2\)
- D \(5 \mathrm{~m} / \mathrm{s}^2\)
Answer & Solution
Correct Answer
(B) \(3 \mathrm{~m} / \mathrm{s}^2\)
Step-by-step Solution
Detailed explanation
The free body diagram for given system is as shown below For ball, \(\Rightarrow \quad m a_1=2 T-m g\) For rod, \(\Rightarrow \quad M a_2=M g-T\) As, thread is uniform and of constant length, so \(2 a_1=a_2\) From Eq. (i), we get \(\frac{m a_2}{2}=2 T-m g\) Multiplying Eq. (ii)…
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