TS EAMCET · Physics · Magnetic Properties of Matter
At a certain place in the magnetic meridian, the earth's magnetic field is twice its vertical component. The ratio of horizontal component of earth's magnetic field and the total magnetic field of the earth at that place is
- A \(\sqrt{3}: 2\)
- B \(1: 2\)
- C \(1: \sqrt{3}\)
- D \(1: 3\)
Answer & Solution
Correct Answer
(A) \(\sqrt{3}: 2\)
Step-by-step Solution
Detailed explanation
\(B = 2V\) \(B^2 = H^2 + V^2 \Rightarrow (2V)^2 = H^2 + V^2\) \(4V^2 = H^2 + V^2 \Rightarrow H^2 = 3V^2 \Rightarrow H = \sqrt{3}V\) \(\frac{H}{B} = \frac{\sqrt{3}V}{2V} = \frac{\sqrt{3}}{2}\)
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