TS EAMCET · Physics · Magnetic Effects of Current
Force acting on an electron moving with velocity \(\mathbf{v}\) in a magnetic field \(\mathbf{B}\) is ( \(e\) is the charge of electron)
- A \(e(\mathbf{v} \times \mathbf{B})\)
- B \(e(\mathbf{v} \cdot \mathbf{B})\)
- C \(e \frac{\mathbf{v}}{\mathbf{B}}\)
- D \(e \frac{\mathbf{B}}{\mathbf{v}}\)
Answer & Solution
Correct Answer
(A) \(e(\mathbf{v} \times \mathbf{B})\)
Step-by-step Solution
Detailed explanation
By Lorentz's force law, force acting on a charge particle in magnetic field \(\mathbf{B}\) moving with velocity \(\mathbf{v}\) is given by \[ \mathbf{F}=q(\mathbf{v} \times \mathbf{B}) \] where \(q=e\), according to question, then, \(\mathbf{F}=e(\mathbf{v} \times \mathbf{B})\)
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