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TS EAMCET · Physics · Electrostatics

The electric field and electric potential at a point due to a point charge are \(500 \mathrm{NC}^{-1}\) and \(30 \mathrm{~V}\) respectively, then the magnitude of the charge is

  1. A \(1.3 \times 10^{-9} \mathrm{C}\)
  2. B \(3 \times 10^{-12} \mathrm{C}\)
  3. C \(2 \times 10^{-10} \mathrm{C}\)
  4. D \(1.6 \times 10^{-20} \mathrm{C}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(2 \times 10^{-10} \mathrm{C}\)

Step-by-step Solution

Detailed explanation

Electric field, \(\mathrm{E}=500 \mathrm{~N} / \mathrm{C}\) Electric potential, \(\mathrm{V}=30 \mathrm{~V}\). \[ \begin{aligned} & \mathrm{E}=\frac{\mathrm{V}}{\mathrm{r}} \\ & \mathrm{r}=\frac{\mathrm{V}}{\mathrm{E}}=\frac{30}{500}=\frac{3}{50} \mathrm{~m} . \end{aligned} \]…
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