TS EAMCET · Physics · Capacitance
Assume each oil drop consists of a capacitance of \(C\). If combine \(n\) drops to form a bigger drop, then the capacitance of bigger \(\operatorname{drop} C^{\prime}\) would be
- A \(C^{\prime}=\frac{2 n^{1 / 3}}{3} C\)
- B \(C^{\prime}=\frac{5 n^{1 / 3}}{4} C\)
- C \(C^{\prime}=\frac{n^{1 / 3}}{5} C\)
- D \(C^{\prime}=C \cdot n^{1 / 3}\)
Answer & Solution
Correct Answer
(D) \(C^{\prime}=C \cdot n^{1 / 3}\)
Step-by-step Solution
Detailed explanation
Capacitance of an oil drop of radius \(r\) is \(C=4 \pi \varepsilon r\) when \(n\) drops combine to form a large drop of radius \(R\), then \(n \times\) volume of 1 small drop \(=\) volume of 1 large drop…
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