TS EAMCET · Physics · Work Power Energy
A ball of mass \(2 \mathrm{~kg}\) is thrown from a tall building with velocity, \(\mathbf{v}=(20 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{i}}+(24 \mathrm{~m} / \mathrm{s}) \hat{\mathbf{j}}\) at time \(t=0 \mathrm{~s}\). Change in the potential energy of the ball after, \(t=8 \mathrm{~s}\) is (The ball is assumed to be in air during its motion between \(0 \mathrm{~s}\) and \(8 \mathrm{~s}, \hat{\mathbf{i}}\) is along the horizontal and \(\hat{\mathbf{j}}\) is along the vertical direction (Take \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(-2.56 \mathrm{~kJ}\)
- B \(0.52 \mathrm{~kJ}\)
- C \(1.76 \mathrm{~kJ}\)
- D \(-2.44 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(A) \(-2.56 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
Given, velocity of the ball, \(\mathbf{v}=(20 \hat{\mathbf{i}}+24 \hat{\mathbf{j}}) \mathrm{m} / \mathrm{s}\) and mass of the ball, \(m=2 \mathrm{~kg}\) From the equation of motion, when a ball is thrown, \[ \mathbf{v}=\mathbf{u}-\mathbf{g} t \] Substituting the given values in…
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