TS EAMCET · Physics · Magnetic Effects of Current
Arectangular coil of 400 turns and \(10^{-2} \mathrm{~m}^2\) area, carrying a current of 0.5 A is placed in a uniform magnetic field of 1 T such that the plane of the coil makes an angle of \(60^{\circ}\) with the direction of the magnetic field. The initial moment of force acting on the coil in Nm is
- A \(\sqrt{3}\)
- B \(\frac{1}{\sqrt{3}}\)
- C 1
- D \(\frac{\sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
Moment of force \(T=N i A B \cos \theta\) \(\begin{aligned} & =400 \times 0.5 \times 10^{-2} \times 1 \times \cos 60^{\circ} \\ & =400 \times 0.5 \times 10^{-2} \times 1 \times \frac{1}{2}=1 \mathrm{Nm}\end{aligned}\)
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