TS EAMCET · Physics · Units and Dimensions
An energy of \(13.6 \mathrm{eV}\) is equal to
- A \(0.518 \times 10^{-25} \mathrm{kcal}\)
- B \(6.04 \times 10^{-25} \mathrm{kWh}\)
- C \(2.17 \times 10^{-10} \mathrm{~J}\)
- D \(2.17 \times 10^{-15} \mathrm{kN}-\mathrm{m}\)
Answer & Solution
Correct Answer
(B) \(6.04 \times 10^{-25} \mathrm{kWh}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} E & =13.6 \mathrm{eV} \\ & =13.6 \times 1.6 \times 10^{-19} \mathrm{~J}(\text { or W - s) } \\ & =21.76 \times 10^{-19} \mathrm{~W}-\mathrm{s} \\ & =\frac{21.76 \times 10^{-19}}{1000 \times 60 \times 60} \mathrm{~kW}-\mathrm{h} \\ & =6.04 \times 10^{-25}…
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