TS EAMCET · Physics · Work Power Energy
An elevator of mass \(500 \mathrm{~kg}\) is ascending upwards with a constant acceleration \(a=2 \mathrm{~m} / \mathrm{s}^2\). What is the work done by the tension in the elevator cable during its climb by \(12 \mathrm{~m}\) ? (Take, \(g=10 \mathrm{~m} / \mathrm{s}^2\) )
- A \(36 \mathrm{~kJ}\)
- B \(48 \mathrm{~kJ}\)
- C \(72 \mathrm{~kJ}\)
- D \(100 \mathrm{~kJ}\)
Answer & Solution
Correct Answer
(C) \(72 \mathrm{~kJ}\)
Step-by-step Solution
Detailed explanation
Mass of elevator, \(m=500 \mathrm{~kg}\) Acceleration of elevator, \(a=2 \mathrm{~ms}^{-2}\) (upward) When elevator is going upward, then tension in the elevator cable, \(T=m(g+a)=500(10+2)=6000 \mathrm{~N}\) \(\therefore\) Work done by the tension force in the cable,…
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