TS EAMCET · Physics · Work Power Energy
A wheel which is initially at rest is subjected to a constant angular acceleration about its axis. It rotates through an angle of \(15^{\circ}\) in time \(t\) sec. The increase in angle through which it rotates in the next \(2 t \mathrm{sec}\) is
- A \(90^{\circ}\)
- B \(120^{\circ}\)
- C \(30^{\circ}\)
- D \(45^{\circ}\)
Answer & Solution
Correct Answer
(B) \(120^{\circ}\)
Step-by-step Solution
Detailed explanation
If angular acceleration is constant, we have \[ \theta=\omega_0 t+\frac{1}{2} \alpha t^2 \] The given \(\theta=15^{\circ}\) \[ \omega_0=0 \] For the first conditions (time \(=t \mathrm{sec}\) )…
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-

Momentum before collision,
\(
p_1=4 m v_1-2 m v_2
\)
Momentum after collision,
\(
p_2=6 m\left(-5 v_2\right)=-30 m v_2
\)
Conservation of momentum gives,
\(
\begin{gathered}
p_1=p_2 \\
\Rightarrow \quad 4 m v_1-2 m v_2=-30 m v_2 \quad \Rightarrow 4 v_1=-32 v_2 \\
\Rightarrow \quad \frac{v_1}{v_2}=\frac{-32}{4}=-8 \text { or }\left|\frac{v_1}{v_2}\right|=8
\end{gathered}
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