TS EAMCET · Physics · Oscillations
A vibration magnetometer consists of two identical bar magnets placed one over the other such that they are perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field \(2^{5 / 4} \mathrm{~s}\). One of the magnets is removed and if the other magnet oscillates in the same field, then the time period in seconds is :
- A \(2^{1 / 4}\)
- B \(2^{1 / 2}\)
- C 2
- D \(2^{5 / 4}\)
Answer & Solution
Correct Answer
(C) 2
Step-by-step Solution
Detailed explanation
Time period of magnet in vibration magnetometer, \(T=2 \pi \sqrt{\frac{I}{M H}}\) First case, \(T_1=2 \pi \sqrt{\frac{I_1+I_2}{M^{\prime} H}}\) where, \(M=\) resultant magnetic moment of two magnets Here, two identical magnets are placed perpendicular to each other.…
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