TS EAMCET · Physics · Waves and Sound
A source emitting sound is tied to one end of a string of length \(50 \mathrm{~cm}\) and is rotated with an angular speed of 40 \(\mathrm{rad} \mathrm{s}^{-1}\) in the horizontal, plane. The ratio of the maximum and minimum frequencies of the sound heard by an observer standing at a distance of \(10 \mathrm{~m}\) from the fixed end of the string is (speed of sound in air \(=340 \mathrm{~ms}^{-1}\) )
- A \(2: 1\)
- B \(4: 3\)
- C \(6: 5\)
- D \(9: 8\)
Answer & Solution
Correct Answer
(D) \(9: 8\)
Step-by-step Solution
Detailed explanation
Given, \(\omega=40 \mathrm{rad} \mathrm{s}^{-1}, 1=\mathrm{r}=50 \mathrm{~cm}=0.5 \mathrm{~m} \therefore\) Speed \(\mathrm{v}=\mathrm{r} \omega\) or \(\mathrm{v}_{\mathrm{s}}=0.5 \times 40=20 \mathrm{~m} / \mathrm{s}\)…
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