TS EAMCET · Physics · Thermodynamics
A solid of \(2 \mathrm{~kg}\) mass absorbs \(50 \mathrm{~kJ}\) when its temperature is raised from \(20^{\circ} \mathrm{C}\) to \(70^{\circ} \mathrm{C}\). The specific heat capacity of this solid in unit of \(\mathrm{J} / \mathrm{kg}{ }^{\circ} \mathrm{C}\) is
- A 500
- B 1000
- C 1500
- D 750
Answer & Solution
Correct Answer
(A) 500
Step-by-step Solution
Detailed explanation
Heat absorbed by a solid is given by \(\Delta Q=m s \Delta T\) where, \(s=\) specific heat of solid. \(\therefore \quad s=\frac{\Delta Q}{m \cdot \Delta T}=\frac{50 \times 1000}{2 \times\left(70^{\circ}-20^{\circ}\right) \mathrm{C}}\)…
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