TS EAMCET · Physics · Magnetic Effects of Current
A solenoid of length \(2 \mathrm{~m}\) carries a current of \(20 \mathrm{~A}\). The diameter of the solenoid is \(3 \mathrm{~cm}\). If the magnetic field inside the solenoid is \(20 \mathrm{mT}\), then the length of wire forming the solenoid is (assume, \(\mu_0=4 \pi \times 10^{-7} \mathrm{H} / \mathrm{m}\) )
- A 100 m
- B 125 m
- C 175 m
- D 150 m
Answer & Solution
Correct Answer
(D) 150 m
Step-by-step Solution
Detailed explanation
For a solenoid, \(I=20 \mathrm{~A}, l=2 \mathrm{~m}, B=20 \mathrm{mT}=20 \times 10^{-3} \mathrm{~T}\) Diameter, \(d=3 \mathrm{~cm}=3 \times 10^{-2} \mathrm{~m}\) \(\therefore\) Radius, \(r=\frac{3}{2} \times 10^{-2} \mathrm{~m}\) If \(n\) be the number of turns per unit length…
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