TS EAMCET · Physics · Capacitance
A particle of mass and charge is thrown perpendicular to an electric field of intensity with an initial velocity The particle moves a distance perpendicular to the field and a distance along the direction of the field. If then the is given by
- A
- B
- C
- D
Answer & Solution
Correct Answer
(D)
Step-by-step Solution
Detailed explanation
Acceleration of the charged particle is, a=qEm Perpendicular to the field, acceleration is zero. Therefore, x=vt ⇒t=xv Along y direction, using second equation of motion, we have y=0+12at2 ⇒y=12qEmxv2 ⇒y=qEx22mv2 On comparing to given relation, we have…
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