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TS EAMCET · Physics · Work Power Energy

A body is moving up an inclined plane of angle \(\theta\) with an initial kinetic energy \(E\). The coefficient of friction between the plane and the body is \(u\). The work done against friction before the body comes to rest is

  1. A \(\frac{\mu \cos \theta}{E \cos \theta+\sin \theta}\)
  2. B \(E\)
  3. C \(\frac{\mu E \cos \theta}{\mu \cos \theta-\sin \theta}\)
  4. D \(\frac{\mu E \cos \theta}{\mu \cos \theta+\sin \theta}\) Increase in KE, \(\begin{aligned} \frac{p_2^2-p_1^2}{2 m} & =\frac{(10)^2-(8)^2}{2 \times 4} \ & =\frac{100-64}{8}=\frac{36}{8} \ & =4.5 \mathrm{~J}\end{aligned}\)
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Answer & Solution

Correct Answer

(B) \(E\)

Step-by-step Solution

Detailed explanation

Acceleration of a body up a rough inclined plane \(a=g(\mu \cos \theta+\sin \theta)\) From equation of motion \(\begin{aligned} v^2 & =u^2-2 a s \\ 0 & =u^2-2 a s \\ u^2 & =2 a s \end{aligned}\) Initial \(\mathrm{KE}, E=\frac{1}{2} m u^2\)…
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