TS EAMCET · Physics · Nuclear Physics
\(\mathrm{A}_{92} \mathrm{U}^{238}\) nucleus decays to \(\mathrm{a}_{82} \mathrm{~Pb}^{214}\) nucleus. The number of \(\alpha\) and \(\beta^{-}\)particles emitted are
- A 6 and 2
- B 3 and 3
- C 2 and 6
- D 3 and 4
Answer & Solution
Correct Answer
(A) 6 and 2
Step-by-step Solution
Detailed explanation
Number of \(\propto\)-particles \(=\frac{238-214}{4}=6\) Number of \(\beta\)-particles \(=82-(92-6 \times 2)=2\)
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