TS EAMCET · Maths · Probability
If a random variable \(X\) has the following probability distribution, then the mean of \(X\) is \(\begin{array}{|l|c|c|c|c|}\hline X=x i & 1 & 2 & 3 & 5 \ \hline p(X=x i) & 2 k^2 & k & k & k^2 \ \hline \end{array}\)
- A \(\frac{26}{9}\)
- B \(\frac{22}{9}\)
- C \(\frac{24}{9}\)
- D \(\frac{28}{9}\)
Answer & Solution
Correct Answer
(B) \(\frac{22}{9}\)
Step-by-step Solution
Detailed explanation
We know that \(\Sigma P(X)=1\)…
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