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TS EAMCET · Maths · Limits

\[ \lim _{x \rightarrow 2} \frac{\sqrt[3]{6+x}-\sqrt[3]{10-x}}{x-2}= \]

  1. A \(\frac{1}{8}\)
  2. B \(\frac{1}{4}\)
  3. C \(\frac{1}{2}\)
  4. D \(\frac{1}{16}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{4}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \lim _{x \rightarrow 2} \frac{\sqrt[3]{6+x}-\sqrt[3]{10-x}}{x-2} \\ = & \lim _{x \rightarrow 2} \frac{(\sqrt[3]{6+x}-\sqrt[3]{10-x})\left((6+x)^{2 / 3}+(6+x)^{1 / 3}(10-x)^{1 / 3}+(10-x)^{2 / 3}\right)}{(x-2)\left((6+x)^{2 / 3}+(6+x)^{1 / 3}(10-x)^{1 /…

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