TS EAMCET · Maths · Limits
\[ \lim _{x \rightarrow 2} \frac{\sqrt[3]{6+x}-\sqrt[3]{10-x}}{x-2}= \]
- A \(\frac{1}{8}\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{2}\)
- D \(\frac{1}{16}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{4}\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \lim _{x \rightarrow 2} \frac{\sqrt[3]{6+x}-\sqrt[3]{10-x}}{x-2} \\ = & \lim _{x \rightarrow 2} \frac{(\sqrt[3]{6+x}-\sqrt[3]{10-x})\left((6+x)^{2 / 3}+(6+x)^{1 / 3}(10-x)^{1 / 3}+(10-x)^{2 / 3}\right)}{(x-2)\left((6+x)^{2 / 3}+(6+x)^{1 / 3}(10-x)^{1 /…
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