TS EAMCET · Maths · Binomial Theorem
In the expansion of \((x-2 y+3 z)^5\), if the total number of terms is \(p\) and the coefficient of \(x^2 y z^2\) is \(q\), then \(\frac{q}{p}=\)
- A \(60\)
- B \(-\frac{180}{7}\)
- C \(72\)
- D \(-\frac{1080}{7}\)
Answer & Solution
Correct Answer
(A) \(60\)
Step-by-step Solution
Detailed explanation
\((x-2 y+3 z)^5\) Total number of terms \(={ }^{5+3-1} C_{3-1}={ }^7 C_2\) \[ \therefore \quad p=21 \] Coefficient of \(x^2 y z^2=\frac{5 !}{2 ! \cdot 1 ! \cdot 2 !}(1)^2(-2)^1(3)^2\)…
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