TS EAMCET · Maths · Permutation Combination
If all the numbers which are greater than 6000 and less than 10000 are formed with the digits \(3,5,6,7,8\) without repetition of the digits, then the difference between the number of odd numbers and the number of even numbers among them is
- A \({ }^4 \mathrm{P}_3\)
- B \(3\left({ }^4 P_2\right)\)
- C \({ }^5 \mathrm{P}_3\)
- D \(2\left({ }^4 \mathrm{P}_3\right)\)
Answer & Solution
Correct Answer
(A) \({ }^4 \mathrm{P}_3\)
Step-by-step Solution
Detailed explanation
Number greater than 6000 and less than 10000 is a 4-digit number cannot start from 3,5 Now, even number can onily end with 6 or 8 Total number between \(6000-10000\) ending with 6 \(={ }^2 \mathrm{C}_1 \times{ }^3 \mathrm{P}_2 \times 6=2!\times 3!=12\) Total even numbers…
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