TS EAMCET · Maths · Functions
\(x=\frac{1}{2}\left(\sqrt{3}+\frac{1}{\sqrt{3}}\right)\), then \(\frac{\sqrt{x^2-1}}{x-\sqrt{x^2-1}}\) is equal to
- A 1
- B 2
- C 3
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(A) 1
Step-by-step Solution
Detailed explanation
Given that or \(\begin{aligned} x & =\frac{1}{2}\left(\sqrt{3}+\frac{1}{\sqrt{3}}\right) \\ x^2 & =\frac{1}{4}\left(3+\frac{1}{3}+2\right)=\frac{4}{3} \end{aligned}\) Now,…
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