TS EAMCET · Maths · Indefinite Integration
If \(x \neq(2 n+1) \frac{\pi}{2}, n \in \mathbb{Z}\) and \(\cos x \neq \frac{-1}{2}\) then \[ \int\left(\frac{\sin x+\sin 2 x}{1+\cos x+\cos 2 x}\right)^2 d x= \]
- A \(\frac{\tan ^3 x}{3}-x+c\)
- B \(\frac{\sec ^3 x}{3}-x+c\)
- C \(\cot x-x+c\)
- D \(\tan x-x+c\)
Answer & Solution
Correct Answer
(D) \(\tan x-x+c\)
Step-by-step Solution
Detailed explanation
We have \(\int\left(\frac{\sin (x)+\sin (2 x)}{1+\cos (x)+\cos (2 x)}\right)^2 d x\)…
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