TS EAMCET · Maths · Quadratic Equation

Assertion $(A) : 3 x^{2} - 16 x + 4 > - 16$ is satisfied for some values of real $x$ in $(0, \frac{10}{3})$ . Reason $(R) : a x^{2} + b x + c$ and $a$ will have the same sign for some values of $x \in R$ when $b^{2} - 4 a c > 0$ . The correct option among the following is

A $(A)$ is true, $(R)$ is true and $(R)$ is the correct explanation for $(A)$
B $(A)$ is true, $(R)$ is true but $(R)$ is not the correct explanation for $(A)$
C $(A)$ is true, but $(R)$ is false
D $(A)$ is false, but $(R)$ is true

Verified Solution

Answer & Solution

Correct Answer

(D) $(A)$ is false, but $(R)$ is true

Step-by-step Solution

Detailed explanation

Given that 3x2-16x+20=fx here a=3, b=-16 & c=20 a>0 & D=b2-4ac=256-240>0 fx>0 ⇒3x2-16x+20>0 ⇒3x-10x-2>0 ⇒x∈ -∞,2∪103,∞. Hence, A is false, but R is true

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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Assertion A: 3x2-16x+4>-16 is satisfied for some values of real x in 0,103. Reason R: ax2+bx+c and a will have the same sign for some values of x∈R when b2-4ac>0. The correct option among the following is

Step-by-step Solution

Assertion $(A) : 3 x^{2} - 16 x + 4 > - 16$ is satisfied for some values of real $x$ in $(0, \frac{10}{3})$ . Reason $(R) : a x^{2} + b x + c$ and $a$ will have the same sign for some values of $x \in R$ when $b^{2} - 4 a c > 0$ . The correct option among the following is