TS EAMCET · Maths · Limits
\(\lim _{x \rightarrow 0} \frac{x^4+x^3+x^2}{\sin ^{-1}\left(\frac{x}{\sqrt{1+x^2}}\right) \cdot \tan ^{-1} x}=\)
- A \(\frac{1}{\sqrt{2}}\)
- B \(0\)
- C \(1\)
- D \(\frac{-1}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(C) \(1\)
Step-by-step Solution
Detailed explanation
Let \(L=\lim _{x \rightarrow 0} \frac{x^4+x^3+x^2}{\sin ^{-1}\left(\frac{x}{\sqrt{1+x^2}}\right) \tan ^{-1} x}\)…
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