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TS EAMCET · Maths · Limits

\(\lim _{x \rightarrow 0} \frac{x^4+x^3+x^2}{\sin ^{-1}\left(\frac{x}{\sqrt{1+x^2}}\right) \cdot \tan ^{-1} x}=\)

  1. A \(\frac{1}{\sqrt{2}}\)
  2. B \(0\)
  3. C \(1\)
  4. D \(\frac{-1}{\sqrt{2}}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(1\)

Step-by-step Solution

Detailed explanation

Let \(L=\lim _{x \rightarrow 0} \frac{x^4+x^3+x^2}{\sin ^{-1}\left(\frac{x}{\sqrt{1+x^2}}\right) \tan ^{-1} x}\)…