TS EAMCET · Maths · Functions
Given that \(a, b \in\{0,1,2, \ldots, 9\}\) with \(a+b \neq 0\) and that \(\left(a+\frac{b}{10}\right)^x=\left(\frac{a}{10}+\frac{b}{100}\right)^y=1000 . \quad\) Then, \(\frac{1}{x}-\frac{1}{y}\) is equal to
- A \(1\)
- B \(\frac{1}{2}\)
- C \(\frac{1}{3}\)
- D \(\frac{1}{4}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
Given that, \(\left(a+\frac{b}{10}\right)^x=\left(\frac{a}{10}+\frac{b}{100}\right)^y=1000\) Let \(\quad a=0\) and \(b=1\)…
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