ExamBro
ExamBro
TS EAMCET · Maths · Functions

Given that \(a, b \in\{0,1,2, \ldots, 9\}\) with \(a+b \neq 0\) and that \(\left(a+\frac{b}{10}\right)^x=\left(\frac{a}{10}+\frac{b}{100}\right)^y=1000 . \quad\) Then, \(\frac{1}{x}-\frac{1}{y}\) is equal to

  1. A \(1\)
  2. B \(\frac{1}{2}\)
  3. C \(\frac{1}{3}\)
  4. D \(\frac{1}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{1}{3}\)

Step-by-step Solution

Detailed explanation

Given that, \(\left(a+\frac{b}{10}\right)^x=\left(\frac{a}{10}+\frac{b}{100}\right)^y=1000\) Let \(\quad a=0\) and \(b=1\)…