TS EAMCET · Maths · Application of Derivatives
A stone thrown upwards, has its equation of motion \(s=490 t-4.9 t^2\). Then the maximum height reached by it, is
- A 24500
- B 12500
- C 12250
- D 25400
Answer & Solution
Correct Answer
(C) 12250
Step-by-step Solution
Detailed explanation
Given that \(s=490 t-4.9 t^2\) On differentiating w.r.t. \(t\), we get \(\frac{d s}{d t}=490-9.8 t\) A stone is reached the maximum height, when \(\frac{d s}{d t}=0\) \(\begin{array}{cc} \Rightarrow & 490-9.8 t=0 \\ \Rightarrow & t=\frac{490}{9.8}=\frac{100}{2}=50 \end{array}\)…
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