TS EAMCET · Chemistry · Solutions
A camphor sample melts at \(176^{\circ} \mathrm{C} . K_f\) for camphor is \(40 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\). A solution of \(0.02 \mathrm{~g}\) of a hydrocarbon in \(0.8 \mathrm{~g}\) of camphor melts at \(156.77^{\circ} \mathrm{C}\). The hydrocarbon is made up of \(92.3 \%\) of carbon. What is the molecular formula of the hydrocarbon?
- A \(\mathrm{C}_6 \mathrm{H}_6\)
- B \(\mathrm{C}_{12} \mathrm{H}_{12}\)
- C \(\mathrm{C}_4 \mathrm{H}_4\)
- D \(\mathrm{C}_8 \mathrm{H}_8\)
Answer & Solution
Correct Answer
(C) \(\mathrm{C}_4 \mathrm{H}_4\)
Step-by-step Solution
Detailed explanation
Melting point of camphor \(=176^{\circ} \mathrm{C}\) \(\left(K_f\right)\) for camphor \(=40 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\) Mass of hydrocarbon \(\left(w_B\right)=0.02 \mathrm{~g}\) Mass of camphor \(\left(w_A\right)=0.8 \mathrm{~g}\) Temperature of camphor (at…
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