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TS EAMCET · Maths · Straight Lines

A quadrilateral ABCD is divided by the diagonal AC into two triangles of equal areas. If A, B, C are respectively 3,4, -3,6, -5,1, then the locus of D is

  1. A x-8y-57x-8y+11=0
  2. B x-8y-57x-8y-11=0
  3. C 3x-8y-573x-8y+11=0
  4. D 3x-8y-113x-8y+57=0
Verified Solution

Answer & Solution

Correct Answer

(D) 3x-8y-113x-8y+57=0

Step-by-step Solution

Detailed explanation

Given points are A(3,4), B(-3,6), C(-5,1), D(x,y). Here area of ABC=Area of ACD. Area of ABC=12∑x1y2-y3 =1236-1+-31-4+-54-6 =1235+-3-3+-5-2 =1215+9+10 =17  ...1 Area of ACD=12∑x1y2-y3 =1231-y+-5y-4+x4-1 =123-3y-5y+20+3x…