TS EAMCET · Maths · Probability
Two players A and B alternatively toss 3 . coins simultaneously. The player who gets 2 heads and 1 tail first, wins the game. If game continues until someone wins and if \(A\) begins the game, the probability that \(B\) wins the game is
- A \(\frac{24}{39}\)
- B \(\frac{4}{7}\)
- C \(\frac{15}{39}\)
- D \(\frac{3}{7}\)
Answer & Solution
Correct Answer
(C) \(\frac{15}{39}\)
Step-by-step Solution
Detailed explanation
Let probability of \(A\) to win \(=P(A)\) and Probability of \(B\) to win \(=P(B)\) If Probability of \(A\) to loss \(=P(A)\) and Probability of \(B\) to loss \(=P\left(B^{\prime}\right)\) Also \(P(2\) head 1 tail \()=\frac{3}{8}\)…
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