TS EAMCET · Maths · Straight Lines
If \(s\) and \(p\) are respectively the sum and the product of the slopes of the lines \(3 x^2-2 x y-15 y^2=0\), then \(s: p\) is equal to
- A 4 : 3
- B 2 : 3
- C 3 : 5
- D 3 : 4
Answer & Solution
Correct Answer
(B) 2 : 3
Step-by-step Solution
Detailed explanation
Given pair of lines is \(3 x^2-2 x y-15 y^2=0\) on compare with, \(\begin{aligned} & a x^2+2 h x y+b y^2=0 \\ \Rightarrow \quad & a=3, h=-1, b=-15 \end{aligned}\) Now, sum of slopes, \(s=m_1+m_2=\frac{-2 h}{b}=\frac{-2(-1)}{-15}=\frac{-2}{15}\) and product of slopes…
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