TS EAMCET · Maths · Probability
Two fair dice are rolled. The probability of the sum of digits on their faces to be greater than or equal to 10 is
- A \(\frac{1}{5}\)
- B \(\frac{1}{4}\)
- C \(\frac{1}{8}\)
- D \(\frac{1}{6}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{6}\)
Step-by-step Solution
Detailed explanation
Total samle points, \(n(S)=6 \times 6=36\) Favourable events \[ =[(6,4),(6,5),(6,6),(5,5),(5,6),(4,6)] \] Total favourable events, \(n(E)=6\) Required probability \[ =\frac{n(E)}{n(S)}=\frac{6}{36}=\frac{1}{6} \]
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