TS EAMCET · Maths · Properties of Triangles
If \(\frac{\tan 3 A}{\tan A}=a\), then \(\frac{\sin 3 A}{\sin A}\) is equal to
- A \(\frac{2 a}{a+1}\)
- B \(\frac{2 a}{a-1}\)
- C \(\frac{a}{a+1}\)
- D \(\frac{a}{a-1}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 a}{a-1}\)
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