TS EAMCET · Chemistry · Surface Chemistry
The coagulation of \(200 \mathrm{ml}\) of a positive colloid took place when \(0.73 \mathrm{~g}\) of \(\mathrm{HCl}\) was added to it without changing the volume much. The flocculation value of \(\mathrm{HCl}\) for the colloid is
- A 1000
- B 0.365
- C 200
- D 100
Answer & Solution
Correct Answer
(D) 100
Step-by-step Solution
Detailed explanation
\(200 \mathrm{~mL}\) of sol \(=0.73 \mathrm{~g} \mathrm{HCl}\) \(\mathrm{mmol}\) of \(\mathrm{HCl}=\frac{0.73 \mathrm{~g}}{36.5 \mathrm{~g} / \mathrm{mol}}=20 \mathrm{mmol}\) \(100 \mathrm{~mL}\) of sol require \(=\frac{1000}{200} \times 20=100 \mathrm{mmol}\). Therefore, the…
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