TS EAMCET · Maths · Application of Derivatives
The \(x\)-coordinate changes on the curve \(y=3 x^5+15 x-8\) at the rate of \(\frac{1}{5}\) units/sec. \(A\left(x_1, y_1\right), B\left(x_2, y_2\right)\) are the points on the curve at which the \(y\)-coordinate changes at the rate of 6 units \(/ \mathrm{sec}\), then the slope of \(A B=\)
- A 10
- B \(\tan ^{-1}\left(\frac{1}{2}\right)\)
- C 18
- D \(\tan ^{-1} 2\)
Answer & Solution
Correct Answer
(C) 18
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Given, } y=3 x^5+15 x-8 \\ & \quad \frac{d x}{d t}=\frac{1}{5} \text { unit } / \mathrm{sec} \Rightarrow \frac{d y}{d t}=6 \text { unit } / \mathrm{sec} \\ & \frac{d y}{d t}=\left(15 x^4+15\right) \frac{d x}{d t} \\ & \Rightarrow \quad…
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