TS EAMCET · Maths · Permutation Combination
5 boys and 5 girls have to sit around a table. The number of ways in which all of them can sit so that no two boys and no two girls are together is
- A \(14400\)
- B \(2880\)
- C \(576\)
- D \(625\)
Answer & Solution
Correct Answer
(B) \(2880\)
Step-by-step Solution
Detailed explanation
Number of ways to arrange 5 boys around a table: \((5-1)! = 4! = 24\) Number of ways to arrange 5 girls in the 5 spaces between the boys: \(5! = 120\) Total ways: \(4! \times 5! = 24 \times 120 = 2880\)
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