TS EAMCET · Maths · Probability
\(A\) and \(B\) are two events of a random experiment such that \(P(B)=0.4, P(A \cap \bar{B})=0.5\), \(\mathrm{P}(\mathrm{A} \cup \mathrm{B})+\mathrm{P}\left(\frac{\mathrm{B}}{\mathrm{A} \cup \overline{\mathrm{B}}}\right)=1.15\), then \(\mathrm{P}(\mathrm{A})=\)
- A 0.9
- B 0.8
- C 0.7
- D 0.25
Answer & Solution
Correct Answer
(C) 0.7
Step-by-step Solution
Detailed explanation
\(P(A \cap \bar{B}) = P(A) - P(A \cap B)\) \(0.5 = P(A) - P(A \cap B) \Rightarrow P(A \cap B) = P(A) - 0.5\) \(P(A \cup B) = P(A) + P(B) - P(A \cap B) = P(A) + 0.4 - (P(A) - 0.5) = 0.9\) \(P(\bar{B}) = 1 - P(B) = 1 - 0.4 = 0.6\)…
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