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TS EAMCET · Maths · Probability

\(A\) and \(B\) are two events of a random experiment such that \(P(B)=0.4, P(A \cap \bar{B})=0.5\), \(\mathrm{P}(\mathrm{A} \cup \mathrm{B})+\mathrm{P}\left(\frac{\mathrm{B}}{\mathrm{A} \cup \overline{\mathrm{B}}}\right)=1.15\), then \(\mathrm{P}(\mathrm{A})=\)

  1. A 0.9
  2. B 0.8
  3. C 0.7
  4. D 0.25
Verified Solution

Answer & Solution

Correct Answer

(C) 0.7

Step-by-step Solution

Detailed explanation

\(P(A \cap \bar{B}) = P(A) - P(A \cap B)\) \(0.5 = P(A) - P(A \cap B) \Rightarrow P(A \cap B) = P(A) - 0.5\) \(P(A \cup B) = P(A) + P(B) - P(A \cap B) = P(A) + 0.4 - (P(A) - 0.5) = 0.9\) \(P(\bar{B}) = 1 - P(B) = 1 - 0.4 = 0.6\)…