TS EAMCET · Maths · Functions
The value of \(\left\{x \in \mathbb{R} \mid\left[\log (1.6)^{1-x^2}-(0.625)^{6(1+x)}\right] \in \mathbb{R}\right\}\) is
- A \((-\infty,-1) \cup(7, \infty)\)
- B \((-1,5)\)
- C \((1,7)\)
- D \((-1,7)\)
Answer & Solution
Correct Answer
(A) \((-\infty,-1) \cup(7, \infty)\)
Step-by-step Solution
Detailed explanation
\[ \left.x \in \mathbb{R} \mid \log \left[(1.6)^{1-x^2}-(0.625)^{6(1+x)}\right] \in \mathbb{R}\right\} \] Now, \(\quad(1.6)^{1-x^2}>(0.625)^{6(1+x)}\)…
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