TS EAMCET · Maths · Properties of Triangles
In a triangle, if \(r_1=2 r_2=3 r_3\), then \(\frac{a}{b}+\frac{b}{c}+\frac{c}{a}\) is equal to
- A \(\frac{75}{60}\)
- B \(\frac{155}{60}\)
- C \(\frac{176}{60}\)
- D \(\frac{191}{60}\)
Answer & Solution
Correct Answer
(D) \(\frac{191}{60}\)
Step-by-step Solution
Detailed explanation
Given that, \(r_1=2 r_2=3 r_3\) \[ \therefore \quad \frac{\Delta}{s-a}=\frac{2 \Delta}{s-b}=\frac{3 \Delta}{s-c}=\frac{\Delta}{k} \] Then, \(s-a=k, s-b=2 k, s-c=3 k\)…
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