TS EAMCET · Chemistry · p Block Elements (Group 13 & 14)
\(\mathrm{SiCl}_4\) on hydrolysis forms ' \(X\) ' and \(\mathrm{HCl}\). Compound ' \(X\) ' loses water at \(1000^{\circ} \mathrm{C}\) and gives ' \(Y\) '. Compounds ' \(X\) ' and ' \(Y\) ' respectively are
- A \(\mathrm{H}_2 \mathrm{SiCl}_6, \mathrm{SiO}_2\)
- B \(\mathrm{H}_4 \mathrm{SiO}_4, \mathrm{Si}\)
- C \(\mathrm{SiO}_2, \mathrm{Si}\)
- D \(\mathrm{H}_4 \mathrm{SiO}_4, \mathrm{SiO}_2\)
Answer & Solution
Correct Answer
(D) \(\mathrm{H}_4 \mathrm{SiO}_4, \mathrm{SiO}_2\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{r}\mathrm{SiCl}_4+4 \mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{H}_4 \mathrm{SiO}_4+4 \mathrm{HCl} \\ \mathrm{H}_4 \mathrm{SiO}_4 \frac{\Delta}{1000^{\circ} \mathrm{C}} \mathrm{SiO}_2+2 \mathrm{H}_2 \mathrm{O}\end{array}\)
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