TS EAMCET · Maths · Differential Equations
The solution of the differential equation \(\sqrt{1-y^2} d x+x d y-\sin ^{-1} y d y=0\), is
- A \(x=\sin ^1 y-1+c e^{\sin ^{-1} y}\)
- B \(y=x \sqrt{1-y^2}+\sin ^1 y+c\)
- C \(x=1+\sin ^1 y+c e^{\sin ^{-1} y}\)
- D \(y=\sin ^1 y-1+x \sqrt{1-y^2}+c\)
Answer & Solution
Correct Answer
(A) \(x=\sin ^1 y-1+c e^{\sin ^{-1} y}\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} & \sqrt{1-y^2} d x+x d y-\sin ^{-1} y d y=0 \\ & \frac{d x}{d y}+\frac{x}{\sqrt{1-y^2}}=\frac{\sin ^{-1} y}{\sqrt{1-y^2}} \\ & \operatorname{IF}=e^{\int \frac{d y}{\sqrt{1-y^2}}}=e^{\sin ^{-1} y} \end{aligned} \] Solution of given differential…
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