TS EAMCET · Maths · Differential Equations
The solution of \(\frac{d y}{d x}+1=e^{x+y}\) is
- A \(e^{-(x+y)}+x+c=0\)
- B \(e^{-(x+y)}-x+c=0\)
- C \(e^{x+y}+x+c=0\)
- D \(e^{x+y}-x+c=0\)
Answer & Solution
Correct Answer
(A) \(e^{-(x+y)}+x+c=0\)
Step-by-step Solution
Detailed explanation
Given, \(\quad \frac{d y}{d x}+1=e^{x+y}\) Put \(x+y=z\)…
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