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TS EAMCET · Maths · Trigonometric Equations

In a ABC, if C=90°, a2+b2a2-b2sin(A-B)=1 and 0<B<45°, then

  1. A a>b>c
  2. B c>a>b
  3. C c>b>a
  4. D a<b<c
Verified Solution

Answer & Solution

Correct Answer

(B) c>a>b

Step-by-step Solution

Detailed explanation

We have  a2+b2a2-b2sin(A-B)=1 ⇒ sin(A-B)=a2-b2a2+b2  ...1 Given, 0<B<45° and ∠C=90° So, 0<A-B<90° ⇒0<sin A-B<1  ⇒ 0<a2-b2a2+b2<1 (from 1)…