TS EAMCET · Maths · Indefinite Integration
If \(\frac{3 x^4-2 x^2+1}{(x-2)^4}=A+\frac{B}{x-2}+\frac{C}{(x-2)^2}+\frac{D}{(x-2)^3}+\frac{E}{(x-2)^4}\), then \(2 A+3 B-C-D+E=\)
- A 0
- B 1
- C -11
- D -39
Answer & Solution
Correct Answer
(D) -39
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