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TS EAMCET · Maths · Indefinite Integration

If \(\frac{3 x^4-2 x^2+1}{(x-2)^4}=A+\frac{B}{x-2}+\frac{C}{(x-2)^2}+\frac{D}{(x-2)^3}+\frac{E}{(x-2)^4}\), then \(2 A+3 B-C-D+E=\)

  1. A 0
  2. B 1
  3. C -11
  4. D -39
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Answer & Solution

Correct Answer

(D) -39

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Detailed explanation

\(\frac{3 x^4-2 x^2+1}{(x-2)^4}\)…
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