TS EAMCET · Maths · Indefinite Integration
If \(\int \frac{9 x+15}{x^3-6 x-9} d x=A \log |g(x)|\) \(+B \log |f(x)|+C\), then \(\frac{(A-B) g(4)}{f(-1)}=\)
- A 3
- B \(\frac{1}{7}\)
- C 1
- D \(\frac{3}{7}\)
Answer & Solution
Correct Answer
(A) 3
Step-by-step Solution
Detailed explanation
We have, \(\int \frac{9 x+15}{x^3-6 x-9} d x=A \log |g(x)|+B \log |f(x)|+C\) Now, \(\frac{9 x+15}{x^3-6 x-9}=\frac{9 x+15}{(x-3)\left(x^2+3 x+3\right)}\) \(\therefore \frac{9 x+15}{(x-3)\left(x^2+3 x+3\right)}=\frac{A}{x-3}+\frac{B x+C}{x^2+3 x+3}\)…
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