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TS EAMCET · Maths · Indefinite Integration

If \(\int \frac{9 x+15}{x^3-6 x-9} d x=A \log |g(x)|\) \(+B \log |f(x)|+C\), then \(\frac{(A-B) g(4)}{f(-1)}=\)

  1. A 3
  2. B \(\frac{1}{7}\)
  3. C 1
  4. D \(\frac{3}{7}\)
Verified Solution

Answer & Solution

Correct Answer

(A) 3

Step-by-step Solution

Detailed explanation

We have, \(\int \frac{9 x+15}{x^3-6 x-9} d x=A \log |g(x)|+B \log |f(x)|+C\) Now, \(\frac{9 x+15}{x^3-6 x-9}=\frac{9 x+15}{(x-3)\left(x^2+3 x+3\right)}\) \(\therefore \frac{9 x+15}{(x-3)\left(x^2+3 x+3\right)}=\frac{A}{x-3}+\frac{B x+C}{x^2+3 x+3}\)…